Question

7 A steel sphere is released from a height

of 9 m on the surface of the Moon. It is
known that the acceleration due to gravity
on the Moon is 1 the acceleration due
6
to gravity on the surface of the Earth.
Calculate the time taken by the sphere to
hit the surface of the Moon.
A 1.8 S
C 3.3 s
B 2.6 s
D 4.2 s​

Answer 1

C 3.3 s

Step-by-step explanation:

Given:

Δy = 9 m

v₀ = 0 m/s

a = ⅙ (9.8 m/s²) = 1.63 m/s²

Find: t

Δy = v₀ t + ½ at²

9 m = (0 m/s) t + ½ (1.63 m/s²) t²

t = 3.3 s