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11 votes
1978 JAMB PHYSICS
man walks 1 km due east and then 1 km due north. His displacement is

User Diegosasw
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1 Answer

18 votes
18 votes

Answer: √2km N45°E

Explanation:His displacement is the shortest distance from his starting point, so, the hypotenuse represent his displacement. Using the four cardinal point diagram, mark 1km due east on the diagram and the from that point, 1km due North, and then join the start and the end point together to form a right-angled triangle! Then solve using Pythagoras theorem or triangle method to find your displacement and using SOHCAHTOA, you can find the angle of displacement or the direction.

Pythagoras theorem

Hyp² = opp² + adj²

SOHCAHTOA means

Sin ∅ = Opp/hyp

Cos ∅ = adj/hyp

Tan ∅ = opp/adj

Using any of those, you will have the same answer for your direction.

User Illia Yaremchuk
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