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The vertex of this parabola is at 2, -1 When the y-value is 0 the x value is 5 what is the coefficient of the squared term in the parabola equation.

A. -3
B. -4
C. 4
D. 3

User Netdigger
by
8.1k points

2 Answers

7 votes

Answer:

Fot this parabola the coefficient for squared term is 7

Explanation:

The formula for vertex equation is:

x = a*(y-h)^{2}+kx=a∗(y−h)

2

+k

if vertex is at (-3,-1) and in the formula the vertex is (k,h), we replace this values

x = a*(y +1)^{2} -3x=a∗(y+1)

2

−3

The other point of this parabola is (4,0), so we replace it in the formula below:

4 = a*(0 + 1)^{2} -34=a∗(0+1)

2

−3

4 = a*(1)-34=a∗(1)−3

4 +3= a*(1)4+3=a∗(1)

a=7a=7

The vertex of this parabola is at 2, -1 When the y-value is 0 the x value is 5 what-example-1
User Johngeek
by
8.2k points
4 votes

Answer:


\large \boxed{\sf (1)/(9)}

Explanation:


\sf y=a(x-h)^2+k


\sf Vertex = (h,k)

y-value is 0 and the x value is 5

h = 2

k = -1


\sf 0=a(5-2)^2+-1

Solve for
\sf a (the coefficient of the squared term).


\sf 0=a(3)^2+-1


\sf 0=9a-1


\sf 9a=1


\displaystyle \sf a=(1)/(9)

The coefficient of the squared term in the parabola equation is 1/9.

User Peter Corless
by
8.9k points

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