Question

How many grams of HNO3 is needed to make 1.5 L of a 3 M solution of HNO3?

Answer 1

`m_(HNO_3)=283.5gHNO_3`

Step-by-step explanation:

Hello,

In this case, since the molarity is defined in terms of the moles of solute and the volume of solution in liters as follows:

`M=(mol)/(V)`

In such a way, solving for the moles of nitric acid, we obtain:

`mol=M*V=1.5L*3mol/L=4.5molHNO_3`

Finally, since the molar mass of nitric acid is 63 g/mol, the mass is computed as:

`m_(HNO_3)=4.5molHNO_3*(63gHNO_3)/(1molHNO_3) \\\\m_(HNO_3)=283.5gHNO_3`

Regards.