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How many grams if hydrogen are required to form 7.06 moles of NH3
PLEASE HELP

1 Answer

10 votes

Answer:

21.18 gm of H2

Step-by-step explanation:

First you need the reaction equation:

N2 + 3H2 ===> 2 NH3

you can see that 3/2 as many moles of H2 are required as are NH3

this would be 10.59 moles of H2 (7.06 * 3/2)

one mole of H2 = 2 gm

10.59 * 2 = 21.18 gm

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