Question

A rough value of deceleration of a skidding automobile is about 7.0m\s^2.using this how long does it take for a car going at 30m\s to stop after the skid starts.How far dose the car go in this time??​

Answer 1

Step-by-step explanation:

Given:

v₀ = 30 m/s

v = 0 m/s

a = -7.0 m/s²

Find: t and Δx

v = at + v₀

0 m/s = (-7.0 m/s²) t + 30 m/s

t = 4.3 seconds

v² = v₀² + 2aΔx

(0 m/s)² = (30 m/s)² + 2 (-7.0 m/s²) Δx

Δx = 64 meters