Question

Find the zeros of the function. Enter the solutions from least to greatest. f(x) = (x + 2)^2 - 64

Answer 1

-10,6

Explanation:

f(x) = (x + 2)^2 - 64

Set equal to zero

0 = (x + 2)^2 - 64

Add 64 to each side

64 = (x + 2)^2

Take the square root of each side

±sqrt(64) = sqrt((x + 2)^2 )

±8 = x+2

Subtract 2 from each side

±8-2 = x

-8-2 =x

8-2 = x

-10,6