Question

Pls with a clear explanation

Answer 1

Step-by-step explanation:

We know that :

`P = (V^(2) )/(R)`

Resistance of Bulb :

`R = ( V^(2) )/(P ) = \frac{ {(240)}^(2) }{280} = 205.71 \: ohms`

As per Ohms laws :

Current when (V = 200)

`i \: = ( V)/( R) = (200)/(205.71) = 0.97 \: A`