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Please help me. 46 points! Need this asap

Please help me. 46 points! Need this asap-example-1
User JBa
by
8.3k points

2 Answers

5 votes

Answer:


\huge \boxed{\mathrm{39 \ meters}}

Explanation:

The perimeter of the right triangle is required.

The base of the triangle is 7 units.

The height of the triangle is 15 units.

The hypotenuse can be found through Pythagorean theorem.

a² + b² = c²

7² + 15² = c²

49 + 225 = c²

274 = c²

c =
√(274)

Adding all the three sides of the right triangle to get the perimeter.

P = a + b + c

P = 7 + 15 +
√(274)

P = 38.552945...

The perimeter of the right triangle is 39 meters rounded to nearest meter.

User Zlaja
by
8.1k points
4 votes

Answer:

39 meters

Explanation:

We know the bottom distance ( 20-13) = 7

And we know the height 15-0 =15

We can use the Pythagorean theorem to find the hypotenuse

a^2 + b^2 = c^2

7^2 + 15^2 = c^2

49+225 = c^2

274 = c^2

Taking the square root of each side

sqrt(274) = c

We want the perimeter

a+b+c

7+15+sqrt(274)

22+sqrt(274)

22+16.55294536

38.55294536

Rounding to the nearest meter

39 meters

User Cooper Scott
by
7.7k points

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