Question

an object is placed at a distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image​

Answer 1

`\boxed{\sf Position \ of \ the \ image = 6 \ cm}`

`\boxed{\sf Nature \ of \ the \ image = Virtual \ and \ Erect}`

Given:

Object distance (u) = -10 cm

Focal length (f) = 15 cm

To Find:

Image distance (v) and nature of the image

Step-by-step explanation:

Mirror Formula:

`\boxed{\bold{\sf (1)/(v) + (1)/(u) = (1)/(f)}}`

Substituting values of u and f in the equation:

`\sf \implies (1)/(v) -(1)/(10) =(1)/(15)`

`\sf \implies (1)/(v)=(1)/(15) +(1)/(10)`

`\sf \implies (1)/(v)=(2)/(30)+(3)/(30)`

`\sf \implies (1)/(v)=(2+3)/(30)`

`\sf \implies (1)/(v)=(5)/(30)`

`\sf \implies v=(30)/(5)`

`\sf \implies v=6 \ cm`

`\therefore`

Image distance (v) = 6 cm

Nature of the image = Virtual and Erect