Question

Please help me out!!!

Answer 1

`{2}^(28). {3}^( - 20). {9}^(4)`

Multiply the exponent 4 by each of the exponents inside the parentheses.

Hope this helps..

Good Luck!

Answer 2

`= 2^2^8 * 3^-^2^0* 9^4`

Explanation:

`\mathrm{Apply\:exponent\:rule}:\quad \left(a*\:b\right)^n=a^nb^n\\\left(2^7*\:3^(-5)*\:9\right)^4=\left(2^7\right)^4*\left(3^(-5)\right)^4*\:9^4\\=\left(2^7\right)^4\cdot \left(3^(-5)\right)^4\cdot \:9^4\\\\= 2^2^8 * 3^-^2^0* 9^4`