Answer:
135 KJ.
Step-by-step explanation:
The following data were obtained from the question:
Mass of ethanol, C₂H₅OH = 143.45 g
Heat of vaporisation, ∆Hvap = 43.3 kJ/mol
Heat required (Q) =.?
Next, we shall determine the number of mole in 143.45 g of ethanol (C₂H₅OH). This is can be obtained as follow:
Mass of ethanol, C₂H₅OH = 143.45 g
Molar mass of ethanol, C₂H₅OH = (12×2) + (1×5) + 16 + 1
= 24 + 5 + 16 + 1
= 46 g/mol
Mole of ethanol, C₂H₅OH =?
Mole = mass /Molar mass
Mole of ethanol, C₂H₅OH = 143.45/46
Mole of ethanol, C₂H₅OH = 3.118 moles
Finally, we shall determine the heat required to vaporize the ethanol, C₂H₅OH as follow:
Heat of vaporisation, ∆Hvap = 43.3 kJ/mol
Mole of ethanol, C₂H₅OH (n) = 3.118 moles
Heat required (Q) =.?
Q = n•∆Hvap
Q = 3.118 × 43.3
Q = 135 KJ
Therefore, the heat required is 135 KJ