Question

An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average velocity of the airplane for this trip?

Answer 1

The average velocity of the airplane for this trip is 1684.21 km/h

Step-by-step explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity =
`(Displacement )/(Change in time)` = Δx / Δt =
`(x2 - x1)/(t2 - t1)`

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity =
`(Distance traveled)/(Time taken)`

Time =
`(Distance traveled)/(Velocity)`

Therefore, Time =
`(2100km )/(1000km/h)`

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity =
`(Distance traveled)/(Time taken)`

Time =
`(Distance traveled)/(Velocity)`

Therefore, Time =
`(1300km )/(800km/h)`

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity =
`(x2 - x1)/(t2 - t1)`

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity =
`(1300 - 2100)/(1.625 - 2.1)`

Average velocity = 1684.21 km/h