135k views
1 vote
Trig: Solve Quadratic Equations by Factoring help with 2b and 2c

Trig: Solve Quadratic Equations by Factoring help with 2b and 2c-example-1
User Ronkov
by
5.5k points

2 Answers

2 votes

Answer:

2b)x=1/3 or x= -4

2c) x= 0 or x= -2/3

User Gordon Slysz
by
6.3k points
1 vote

Explanation:

To factor ax² + bx + c, use the AC method.

  • Multiply a and c
  • Find factors of ac that add up to b
  • Divide those two factors by a. Reduce the fractions.
  • The numerators are the constants, and the denominators are the coefficients.

(b) 3x² + 11x − 4 = 0

  • a = 3, b = 11, c = -4
  • ac = (3)(-4) = -12
  • Factors of -12 that add up to 11 are 12 and -1.
  • Divide by 3: -1/3 and 12/3 = 4/1
  • The factors are 3x − 1 and x + 4.

(3x − 1) (x + 4) = 0

3x − 1 = 0, or x + 4 = 0

x = 1/3, or x = -4

(c) 12x² + 8x = 0

Here, you can simply factor the greatest common factor, 4x.

4x (3x + 2) = 0

4x = 0, or 3x + 2 = 0

x = 0, or x = -2/3

User Masami
by
5.8k points