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Let a and b 2 positive real number such that a

User Neisha
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1 Answer

3 votes

Answer:

Proved

Explanation:

Given

Integers: a and b

Where
a < b

Required

Show that
a^n < b^n

We start by writing out the given expression


a < b

Then, take nth root of both sides


a^n < b^n

For instance:

Let a = 2, b = 2 and n = 4

First

Since
2 < 3

Then


2^4 < 3^4


16 < 81

Proved

This is so for all positive values of a,b and n where a < b

User Diomedes
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