Answer:
There has been no change in the classifications between the last school year and this school year.
Explanation:
A Chi-square test for goodness of fit will be used in this case.
The hypothesis can be defined as:
H₀: The observed frequencies are same as the expected frequencies.
Hₐ: The observed frequencies are not same as the expected frequencies.
The test statistic is given as follows:
The expected values are computed using the formula:
Here, N = 300
Use Excel to compute the values.
The test statistic value is:
The test statistic value is, 1.662.
The degrees of freedom of the test is:
n - 1 = 4 - 1 = 3
The significance level is, α = 0.05.
Compute the p-value of the test as follows:
p-value = 0.6454
*Use a Chi-square table.
p-value = 0.6454 > α = 0.05.
So, the null hypothesis will not be rejected at 5% significance level.
Thus, concluding that there has been no change in the classifications between the last school year and this school year.