51.9k views
0 votes
Rainwater draining from a neighborhood street initially travels at 4 ft/s through a pipe with a cross-sectional area of 15.7 ft2. This pipe connects down the street to another pipe with a cross-sectional area of 65.4 ft2. What would be the speed of the water as it moves through this larger pipe?

1 Answer

0 votes

Answer:

The velocity is
v_2 = 0.96 \ ft/s

Step-by-step explanation:

From the question we are told that

The initial speed is
v_1 = 4 \ ft/s

The cross -sectional area of the first pipe is
A_1 = 15.7 \ ft

The cross -sectional area of the second pipe is
A_2 = 65.4 \ ft

Generally from continuity equation we have that


A_1 * v_1 = A_2 * v_2

So


v_2 = (A_1 * v_1 )/(A_2 )

=>
v_2 = (15.7 * 4 )/(65.4 )

=>
v_2 = 0.96 \ ft/s

User JJSanDiego
by
4.9k points