Answer:
The first equation can be multiplied by 3 and the second equation by 2.
Explanation:
We are given the following system of equations:
![\boxed{\left \{ {{2x+3y=25} \atop {-3x+4y=22}} \right.}](https://img.qammunity.org/2021/formulas/mathematics/college/zmzolhagygg3llc0dybpl4au68s2ue628q.png)
To eliminate a variable in the equation, they must cancel out. For instance, if x = 1, in order to cancel out the numbers, you must add -1.
To multiply an equation, you must apply the constant that you are multiplying by to all constants and coefficients of the equation. For example, to multiply 2x + 4y = 8 by 3, you must multiply 2x by 3, 4y by 3, and 8 by 3.
Therefore, using this information, you can attempt each answer set and test the possibilities.
Answer Choice A
If you multiply the first equation by -3, you will get -6x - 9y = -75. If you multiply the second equation by 2, you will get -6x + 8y = 44. Adding -6 + -6 gives you -12, so these do not cancel out.
Answer Choice B
If you multiply the first equation by -4, you will get -8x - 12y = -100. If you multiply the second equation by 2, you will get -6x + 8y = 44. Adding -8 + -6 gives you -14, so these do not cancel out.
Answer Choice C
If you multiply the first equation by 3, you will get 6x + 9y = 75. If you multiply the second equation by 2, you will get -6x + 8y = 44. Adding 6 + -6 gives you 0, so these do cancel out.
Answer Choice D
If you multiply the first equation by 4, you will get 8x + 12y = 100. If you multiply the second equation by -3, you will get 9x - 12y = -66. Adding 8 + -9 gives you -1, so these do not cancel out.