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LONGI · Answer 1 · 2021-02-02T07:59:26+0000

Answer:

(D)
$3 \pm i√(3)$

Explanation:

We can solve this using the quadratic formula, where a is 1, b is -6, and c is 12.

$(-b\pm√(b^2-4ac))/(2a)\\\\(-(-6)\pm√(6^2-4\cdot1\cdot12))/(2\cdot1)\\\\(6\pm√(36-48))/(2)\\\\(6\pm√(-12))/(2)\\\\(6\pm i√(12))/(2)\\\\3\pm i√(3)\\\\$

Hope this helped!

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