215k views
4 votes
What is the wavelength of the light entering an interferometer if 402 bright fringes are counted when the movable mirror moves 0.115 mm?

1 Answer

4 votes

Answer:

The value is
\lambda = 572 *10^(-9) \ m

Step-by-step explanation:

From the question we are told that

The number of bright fringes is n = 402

The displacement of the mirror is
\delta l = 0.115 \ mm = 1.15 *10^(-4) \ m

Generally the number of fringes is mathematically represented as


n = (2 * \delta l )/(\lambda )

=>
\lambda = (2 * \delta l )/(n )

=>
\lambda = (2 * 1.15*10^(-4) )/(402 )

=>
\lambda = 572 *10^(-9) \ m

User Suamikim
by
4.4k points