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Solve for n: 4^n×2^-18=1​

User JoyGuru
by
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2 Answers

4 votes

Answer:

n = 9.

Explanation:

4^n = 1 / 2^-18

4^n = 2^18

2^2n = 2^18

2n = 18

n = 9.

User Juanita
by
7.5k points
7 votes

One way to do it is by cleverly rewriting terms and using some basic algebraic identities:


4^n\cdot 2^(-18)=1.


2^(2n-18)=2^0.


2n-18=0.


n=18/2=\boxed{9}.

Another way would be to use logarithms, namely:


4^n\cdot2^(-18)=1\implies n=\log_4\Big({(1)/(2^(-18))}\Big)=\boxed{9}.

Hope this helps.

User Harpreet
by
8.5k points

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