Question

What is the solution set of the following system of
equations?

Answer 1

x=-5, x=0

Explanation:

Substitute Y of first equation into second equation so:
3x+6 =
`(x+4)^2-10`

Add 10 to both sides and expand brackets:

3x + 16 =
`x^2+8x+16`

Collect all terms onto one side:

`x^2+5x=0`

Factorise:

`x(x+5)=0`

The solutions therefore are:

x = -5

and

x = 0