Question

A sheet of aluminum foil weighs 2.07g. If the sheet is 24cm long and 20cm wide, how thick is the sheet in micrometers? The density of aluminum is 2.7 g/cm3.

Answer 1

`h=1.60\mu m`

Step-by-step explanation:

Hello,

In this case, given the density and the mass of the aluminum foil, we can compute the occupied volume as shown below:

`\rho =(m)/(V)\\ \\V=(m)/(\rho)=(2.07g)/(2.7g/cm^3) =0.767cm^3`

Next, since the volume is defined as:

`V=24cm*20cm*h`

Whereas
`h` accounts for its thickness, we can find it to be:

`h=(V)/(24cm*20cm)=(0.767cm^3)/(20cm*24cm)\\ \\h=1.60x10^(-3)cm*(10000\mu m)/(1cm) \\\\h=1.60\mu m`

Regards.