1 Answer

Reggaemahn · Answer 1 · 2021-06-03T04:49:10+0000

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = (1)/(frequency) = (1)/(160) \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$(200)/(60) = (10)/(3) \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$(200)/(65) = (40)/(13) \approx 3.08$ loops per minute

then the period is:

$(13)/(40) =0.325\,\,\,minutes$

Therefore runner B has the smaller period

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