Answer:
acceleration
![\approx 2.78\,\,(m)/(s^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ajbkx8yprd1mwqpwa8ag824eh2fpss1muw.png)
Explanation:
The acceleration is the change in velocity per unit of time.
Therefore to have this rate in appropriate units that can combine, we re-write the change from 0 to 70 km/h in meters per second using:
![70 (km)/(h) = (70000)/(3600) (m)/(s)](https://img.qammunity.org/2021/formulas/mathematics/high-school/irj2zc18nlkxffo7k1bwr2zwy1o9nxj66n.png)
so in this case the acceleration becomes:
![accel=(change\,\,vel)/(change\,\,time) =(70000m)/(3600\,*7\,s^2) \approx 2.78\,\,(m)/(s^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/cvi8x8q04hrcre6o71egjfj5sbe2ngg0je.png)