Question

Find the x-intercepts of the parabola.

g(x)=−x2−6x−5

Answer 1

Answer: The x intercepts are -1 and -5 or (-1,0) and ( -5,0)

Explanation:

Finding the x intercepts of a parabola is the same as finding the roots of a parabola because the x intercept is when y or g(x) is equal to zero. So set the equation equal zero.

`-x^(2) -6x -5 = 0` First divide each term by 0 to get the largest degree coefficient to equal 0.

x^2 + 6x +5 = 0 Now find two numbers that their product is 5 and their sum is 6. The numbers 5 and 1 works out because the 5 times 1 is 5 and 5 plus 1 is 6.

Rewrite the whole equation as

x^2 + 1x+5x +5 = 0 Now factor the left side by grouping

x(x+1) 5(x+1) = 0 Factor out x+1

(x+1) (x+5) = 0 Now use the zero product by setting each of them equal zero.

x+ 1 = 0 or x+5 = 0

-1 -1 -5 -5

x = -1 or x = -5