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What is the minimum number of clients the travel agent should survey? Note that z=1.96 for a 95% confidence interval.

User Felice
by
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1 Answer

3 votes

Answer:

121

Explanation:

Given data as per the question

Standard deviation =
\sigma = 840

Margin of error = E = 150

Confidence level = c = 95%

For 95% confidence, z = 1.96

based on the above information, the minimum number of clients surveyed by the travel agent is


n = ((z* \sigma)/(E))^2


= ((1.96* 840)/(150))^2

= 120.47

= 121

hence, the 121 number of clients to be surveyed

Therefore we applied the above formula to determine the minimum number of clients

User Sylph
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