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A 1000 kg car developed a snag and is standing in the middle of a road. The driver and a help pulled it with two ropes respectively with forces 200√2 N 45° east of south and 400N 30° north of east. Assuming negligible friction, find the acceleration of car

User Dani Akash
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1 Answer

6 votes

Answer:

Acceleration = 0.1464 m/s^2

Step-by-step explanation:

From the question, the parameters given are:

Mass m = 1000 kg

The driver and a help pulled it with two ropes respectively with forces 200√2 N 45° east of south and 400N 30° north of east

Find the resultant force along the x axis.

(400 × cos30) - (200√2 × cos45)

346.4 - 200 = 146.4 N

therefore, the resultant force = 146.4N

The formula to use for the acceleration of the car is

F = ma

Where

F = resultant force

M = mass of the car

a = acceleration of the car

Substitute f and m into the formula

146.4 = 1000 × a

Make a the subject of formula

a = 146.4 / 1000

a = 0.1464 m/s^2

Therefore, the car accelerate at 0.1464 m/s^2

User Sunit Gautam
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