Question

I set a goal to drink 64 ounces of water a day. If I drink 3 1/10 ounces in the morning, 2 1/15 ounces at noon, and 6 5/20 ounces at dinner, how many more ounces of water do I have to drink to reach my goal for the day?

Answer 1

You must drink 52 7/12 ounces or 52.58 ounces to reach the goal.

Explanation:

Total amount of the water already drank is found by adding the fractions

So

3 1/10 ounces + 2 1/15 ounces + 6 5/20

Converting into improper fractions

31/10 + 31/15+ 125/20

Now finding the lcm of 10,15,20

so Factors of 10 = 2 x 5

Factors of 15 = 5 x 3

Factors of 20 = 2 x2 x5

LCM= 5x2x2x3= 60

31*6/60 + 31*4/60 + 125*3/60

= 186+124+375/60

= 685/60 = 11.42 ounces

The amount of water already drank is 11.42 ounces

The amount remaining is found by subtracting the amount drank from the total amount

so

64 ounces - 11.42= 52.58

It can be solved in fractions as

64- 11 5/12

Again taking making improper fraction and taking lcm

64- 137/12

= 768-137/12 = 631/12= 52 7/12 ounces