Answer:
some parts of your question is missing attached below is the missing part
Answer : Fa = 4.46 Ib
Step-by-step explanation:
use the equation
Z = 0.1 sin2∅
next we will differentiate the equation to get the locus of the velocity
z = 0.2 cos2∅∅
differentiate the equation furthermore to get the locus of acceleration in the horizontal axis
z = -0.4sin2∅(∅)^2 + 0.2cos2∅∅
note : express ∅ as 6 rad.
for angular velocity and ∅ = 0 for angular acceleration
equation above becomes :
Z = - 0.4 sin 2∅ ( 6)^2 + 0.2 cos 2∅(0)
= - 14.4 sin 2∅ ( acceleration of the follower in horizontal direction )
next calculate The force at the end of A of the follower
Fa - Kx = mz
note: m = w / g hence : Fa - Kx = w/g z ------- (2)
w = weight of the spring-held follower = 0.75 Ib
x = compression of the spring = 0.4
k = spring stiffness = 12 Ib/ft
∅ = 45⁰
g = 32.2 ft/s^2
input these values into equation 2
hence : Fa = 4.46 Ib ( force at the end A of the follower )