Answer:
Well, we know that there exists a function f(x) such that f(x-1) is a direct transformation of its parent function. First we want to set x=x-1. Conceptually, it might be easier just to annotate one of the x’s as a completely different variable, because we know that x doesn’t equal x-1. So let’s rewrite as x=y-1 and solve for y.
We now have y=x+1 where y(x) is actually our parent function and y(x)=f(x+1). So take our equation f(x-1) and substitute each x with (x+1). So f(x)=2(x+1) + 3
f(x)= 2x + 5. We can check this by finding f(x-1) because it should equal 2x+3.
f(x-1)= 2(x-1) + 5
f(x-1)= 2x + 3.
Hoped I helped