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How do I solve for y in this equation? 3xy-28=15x

User Wijitha
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1 Answer

4 votes

Answer:

x = 28/(3y -15)

Explanation:

Put the x-terms on the same side of the equal sign and everything else on the other side. Divide by the coefficient of x.

3xy -28 = 15x . . . . . . given

-28 = 15x -3xy . . . . . subtract 3xy

-28 = x(15 -3y) . . . . . factor out x

-28/(15 -3y) = x . . . . . . divide by the coefficient of x

We prefer to have a positive sign where possible, so we can multiply this by -1/-1 to get ...

x = 28/(3y -15)

User Nagaraju Jampani
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4.0k points