Question

1+tanA.tan2A = sec2A​

Answer 1

Explanation:

1+tan2A(tanA)=sec2A

Right hand side

sec2A=1cos2A=1cos2A−sin2A

=cos2A+sin2Acos2A−sin2A

=1+tan2A1−tan2A

=1−tan2A+2tan2A1−tan2A

=1−tan2A1−tan2A+2tan2A1−tan2A

=1+2tanA1−tan2A×tanA

=1+tan2A×tanA

=Left hand side

I HOPE THIS WILL HELP YOU

MARK ME AS BRAIN LIST

IF MY ANSWER IS HELP FUL