Question

Can someone please help me???

a is 3/4
b is -8
c is -2
d is 3

Answer 1

Answer: 206

=======================================

Work Shown:

a = 3/4

b = -8

c = -2

d = 3

----------------

c-d = -2-3 = -5

(c-d)^2 = (-5)^2 = 25

a+(c-d)^2 = 3/4 + 25 = 3/4 + 100/4 = 103/4

-b * [ a + (c-d)^2 ] = -(-8)*103/4 = 8*103/4 = (8/4)*103 = 2*103 = 206

----------------

Another way to show the steps could be

`-b[a+(c-d)^2]\\\\-(-8)\left[(3)/(4)+(-2-3)^2\right]\\\\8\left[(3)/(4)+(-5)^2\right]\\\\8\left((3)/(4)+25\right)\\\\8\left((3)/(4)+(100)/(4)\right)\\\\8\left((3+100)/(4)\right)\\\\8\left((103)/(4)\right)\\\\(8)/(4)*103\\\\2*103\\\\206\\\\`

Which is more or less the same thing as the previous section.

----------------

So ultimately,

`-b[a+(c-d)^2] = 206`

when a = 3/4, b = -8, c = -2, and d = 3.

Answer 2

-b[a + (c-d)^2]

-(-8)[3/4 + (-2 -3)^2]

8 [3/4 + (-5)^2]

8 [3/4 + 25]

8 [25.75]

206