92,868 views
34 votes
34 votes
Write the equation of a line perpendicular to 3x + 4y = 6 going through the point (2,-5).

User Ininiv
by
2.7k points

1 Answer

12 votes
12 votes

write the given equation in a standard form

3x + 4y = 6

4y = 6 - 3x

4y = - 3x + 6

divided by 4 in both sides

y = - 4/3x + 3/2

standard form of a linear equation is

y = mx +c

therefore m for gradient is -4/3

the product of the gradient of the lines that are perpendicular to each other is -1

- 4/3 × mx = -1

mx = 3/4

y = mx + c

-5 = 3/4(2) + c

-5 = 3/2 + c

c = -13/2

therefore your equation is

y = 3/4x - 13/2

User Clonk
by
3.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.