Question

A sample of ozone gas occupies 225 mL at 1.00 atm and 0 °C. If the volume of the gas is 625 mL at 25 °C, what is the pressure?

Answer 1

`P_2=0.393atm`

Step-by-step explanation:

Hello,

In this case, we can use the combined ideal gas law in order to analyze its behavior as a function of changing temperature, volume and pressure:

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

Thus, since we know the volume, temperature and pressure at the initial condition, we can compute the final pressure as shown below:

`P_2=(P_1V_1T_2)/(T_1V_2) =(1.00atm*225mL*(25+273)K)/((0+273)K*625mL)\\ \\P_2=0.393atm`

Regards.