Question

(I) A car slows down from 28 m????s to rest in a distance of 88 m. What was its acceleration, assumed constant?

Answer 1

The value is
`a = - 4.45 m/s^2`

Step-by-step explanation:

From the question we are told that

The initial speed is
`u = 28 \ m/s` at a distance of
`s_1 = 0 \ m`

The final speed is
`v = 0 \ m/s` at a distance of
`s_2 = 88 \ m`

Generally from the kinematic equation we have that

`v^2 = u^2 +2as`

=>
`a = (v^2 - u^2 )/( 2(s_2 - s_1 ))`

=>
`a = (0 - 28^2 )/( 2(88 - 0 ))`

=>
`a = - 4.45 m/s^2`

The negative sign shows that it is decelerating