Question

How much energy is transferred when 30.0
g of water is cooled from 25.0 °C to 12.7 °C.

Answer 1

Heat transferred, Q = 1542.42 J

Step-by-step explanation:

Given that,

Mass of water, m = 30 grams

Initial temperature,
`T_i=25^(\circ) C`

Final temperature,
`T_f=12.7^(\circ) C`

We need to find the energy transferred. The energy transferred is given by :

`Q=mc\Delta T`

c is specific heat of water, c = 4.18 J/g °C

So,

`Q=30\ g* 4.18\ J/g-^(\circ) C* (12.7-25)\ ^(\circ) C\\\\Q=-1542.42\ J`

So, 1542.42 J of energy is transferred.