Question

K= 1/2mv^2
K=1/2(210kg)(10.5 m/s)^2

answer:
unit:

Answer 1

11577.25 Joules

Step-by-step explanation:

The expression given in the question which is

`k= (1)/(2) mv^2`

Is the expression for the kinetic energy stored in a system and it is measured in Joules

From the expression we can see that

mass m=210 kg

velocity v= 10.5 m/s

Substituting as seen in the question we have the kinetic energy as

`k= (1)/(2)*210*10.5^2\\\\k= (1)/(2)*210*110.25\\\\k= (1)/(2) *23152.5\\\\k= 11577.25 J`

hence the energy stored is 11577.25 Joules