Question

g A solenoid 63.5 cm long has 960 turns and a radius of 2.77 cm. If it carries a current of 2.28 A, find the magnetic field along the axis at its center.Find the magnetic field on the solenoidal axis at the end of the solenoid.

Answer 1

The value is
`B = 0.0043 \ T`

Step-by-step explanation:

From the question we are told that

The length of the solenoid is
`l = 63.5 = 0.635 \ m`

The number of turns is
`N = 960 \ turns`

The current is
`I = 2.28 \ A`

Generally the magnetic field is mathematically represented as

`B = \mu _o * n * I`

Where n is the number of turn per unit length which is mathematically evaluated as

`n = (N)/(l)`

`n = (960)/(0.635)`

`n = 1512 \ turns /m`

and
`\mu_o` is the permeability of free space with value
`\mu_o = 4\pi * 10^(-7) N/A^2`

So

`B = 4\pi * 10^(-7) * 1512 * 2.28`

`B = 0.0043 \ T`