Answer:
The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.
Step-by-step explanation:
Given;
weight of the man, W = 700 N
Weight of the woman, W = 440 N
momentum is given by;

Kinetic energy of the man;

Momentum of the man is calculated as;

The kinetic energy of the woman is given by;

The momentum of the woman is given;

Since, momentum of the man = momentum of the woman


mass of the mas = 700 / 9.8 = 71.429
mass of the woman is = 440 / 9.8 = 44.898

Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.