Question

The following reaction proceeds at a rate such that 3 mole of A is consumed per minute. Given this, how many moles of C are produced per minute? 2A+2B→4C

Answer 1

For every 3 moles of A consumed in the reaction, 4 moles of C are produced per minute.

Step-by-step explanation:

The reaction: 2A + 2B → 4C means that for every 2 moles of A consumed, 4 moles of C are produced. Given that 3 moles of A are consumed per minute, we can calculate the moles of C produced per minute by using the stoichiometry of the reaction:

3 moles A → 4 moles C

Thus, for every 3 moles of A consumed, 4 moles of C are produced. Therefore, the rate of production of C per minute would be:

(4 moles C / 3 moles A) * 3 moles A/min = 4 moles C/min

Answer 2

6 mol/min

Step-by-step explanation:

2A+2B→4C

The relationship between the reactants and products of this equation is given by;

1/2 -d[A]/dt = 1/2 -d[B]/dt = 1/4 d[C]/dt

Our focus is on A and C

From the question;

d[A]/dt = 3mol/min

We have;

1/2 (3) = 1/4 d[C]/dt

d[C]/dt = 4/2 * 3 = 6 mol/min