Question

Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. Measuring from the center of the pattern, we find that the fifth dark spot is 4.00cm away. What is the spacing between the slits

Answer 1

The value is
`d = 0.000125 \ m`

Step-by-step explanation:

From the question we are told that

The wavelength is
`\lambda = 500 \ nm = 500 *10^(-9 ) \ m`

The distance is of the screen is
`D = 2.0 \ m`

The width of the fifth dark spot is
`y = 4.00 \ cm = 0.04 \ m`

Generally the width of a fringe is mathematically represented as

`y = ( n * \lambda * D )/(d )`

=>
`0.04 = ( 5 * 500 *10^(-9) * 2 )/(d)`

=>
`d = ( 5 * 500 *10^(-9) * 2 )/(0.04)`

=>
`d = 0.000125 \ m`