Question

14. If EF bisects CD, CG = 5x - 1, GD = 7x - 13, EF = 6x - 4, and GF = 13, find EG.

3. EF = 6-a. and Cr -13, cihad ES

Answer 1

Greetings from Brasil....

As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD

5X - 1 = 7X - 13

X = 6

EF = EG + GF

6X - 4 = EG + 13 x = 6, so

6·6 - 4 = EG + 13

EG = 19

(see attachment)