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A part of a circuit contains an inductor. The current through the inductor is changing uniformly from 2.40A to 0.30A over the course of 1.75s. If the EMF ( voltage change ) from one side of the inductor to the other is 5.70 Volts, what is the value of the inductance

User Zaratustra
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1 Answer

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Answer:

The value of the inductance is 4.75 H

Step-by-step explanation:

Given;

initial current through the inductor, I₁ = 2.4 A

final current through the inductor, I₂ = 0.3 A

duration of change of current, dt = 1.75 s

voltage change of the inductor, V = 5.7 Volts

The voltage change of the inductor is given by;


V_L = -L(di)/(dt)\\\\ V_L = -L((I_2-I_1)/(dt) )\\\\V_L = L((I_1-I_2)/(dt) )\\\\

Where;

L is the inductance of the coil;


5.7 = L((2.4-0.3)/(1.75) )\\\\5.7 = 1.2 L\\\\L = (5.7)/(1.2)\\\\ L = 4.75 \ H

Therefore, the value of the inductance is 4.75 H

User Chaos Manor
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