Question

D= 1.246g/cm3 /(1 +8.324x10^-5 K^-1 T) at what temp (K) will the density of this liquid equal 1.212 g/cm3

Answer 1

At 336.6K, the density of the liquid is 1.212g/cm³

Step-by-step explanation:

The density change in a substance with the temperature. As general (But not always applicable) rule, the density decreases with the temperature.

A formula to find density of the liquid of the problem is:

`D = (1.246g/cm^3)/(1+8.324x10^(-5)K^(-1)*T)`

Where D is density and T is absolute temperature (In K).

If we want a density of 1.212g/cm^3:

`1.212g/cm^3 = (1.246g/cm^3)/(1+8.324x10^(-5)K^(-1)*T)\\1.212g/cm^3+1.01x10^(-4)g/cm^3K^(-1)*T = 1.246g/cm^3\\1.01x10^(-4)g/cm^3K^(-1)*T =0.034g/cm^3\\T = 336.6K`

At 336.6K, the density of the liquid is 1.212g/cm³