1 Answer

CenterOrbit · Answer 1 · 2021-04-20T06:54:47+0000

Answer:

x≥2

Explanation:

First, write out the equation as you have it:

$58-10x\leq20+9x$

Then, add
10x to both sides:

$58-10x+10x\leq20+9x+10x\\58\leq20+19x$

Next, subtract
from both sides:

$58-20\leq20-20+19x\\38\leq19x$

Finally, divide both sides by
:

$(38)/(19)\leq(19x)/(19)\\2\leq x$

or

$x\geq 2$

Therefore: the answer to this inequality/equation is: x≥2

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