Question

the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 64 M. the length of the alley is 2 times the width. find the length and the width of the playing alley​

Answer 1

`Length = (64)/(3)m`

`Width= (32)/(3)m`

Explanation:

Given

`Perimeter = 64m`

`Length = 2 * Width`

Required

Determine the length and the width

Since the alley is rectangular, the perimeter is as follows;

`Perimeter = 2 (Length * Width)`

Substitute 64m for Perimeter

`64m = 2(Length + Width)`

Substitute 2 * Width for Length

`64m = 2(Width+ 2 * Width)`

`64m = 2(Width+ 2 Width)`

`64m = 2(3 Width)`

`64m = 6Width`

Divide both sides by 6

`Width= (64m)/(6)`

`Width= (32)/(3)m`

Recall that

`Length = 2 * Width`

`Length = 2 * (32)/(3)m`

`Length = (64)/(3)m`