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The diagonals of a rhombus bisect each other of measures 8cm and 6cm .Find its perimeter. please help !!!!!!!!!!!!!!!!!!!!!!!!

User Ajith Gopi
by
5.3k points

2 Answers

5 votes

Answer:

perimeter = 20 cm

Explanation:

consider breaking the rhombus into four equal parts.

and that gives you a triangle.

(refer to image attached for more clarification)

let a = 3, b = 4

to get the side c, use Pythagorean theorem = c² = a² + b²

c = sqrt (3² + 4²)

side c = 5

therefore,

perimeter = 4 x sides (c)

perimeter = 4 x 5

perimeter = 20 cm

The diagonals of a rhombus bisect each other of measures 8cm and 6cm .Find its perimeter-example-1
User Muhammad Shah
by
5.2k points
3 votes

Answer:

20 cm

Explanation:

20 cm

8/2 = 4

6/2 = 3

3 and 4 are the sides of the triangle (four triangles in rhombus)

a²+b²=c²

4³+3²=c²

c = 5

5 x 4 = 20

Hope this helped

User Bucky
by
5.9k points