Question

Given 57 grams of NO2,

A. How many moles of NO2, are present?

B. How many atoms of oxygen are present?​

Answer 1

N=14 O=16

Step-by-step explanation:

46 g = 1 mole of NO2

Now, 57g =(1/46) ×57 mole of NO2

= 1.24 mole of NO2